(3^y+1)=(9^y-1)

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Solution for (3^y+1)=(9^y-1) equation: 



(3^y+1)=(9^y-1)

We move all terms to the left:

(3^y+1)-((9^y-1))=0

We get rid of parentheses

3^y-((9^y-1))+1=0



We calculate terms in parentheses: -((9^y-1)), so:

(9^y-1)

We get rid of parentheses

9^y-1

Back to the equation:

-(9^y-1)



We get rid of parentheses

3^y-9^y+1+1=0

We add all the numbers together, and all the variables

3^y-9^y+2=0

We move all terms containing y to the left, all other terms to the right

3^y-9^y=-2

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